麦芽地苹果论坛 Mac软件下载 Mac游戏下载»返回首页 › Resources › Mac OS X 软件/Soft › Cardhop 1.2 TNT 破解版 Mac 通讯录软件 返回列表 发新帖 查看: 584 回复: 0. Cardhop for Mac 1.2 Aside from extending Cardhop to iOS, Flexibits today also brought the Mac app to version 1.2. Aside from providing full directory lookup support like in the inaugural iOS version, the update brought a bunch of tweaks, bug fixes and other improvements to the Mac app. The contact managing app Cardhop is launching on iOS today, about a year and a half after debuting on the Mac.Like the Mac app, the iOS version of Cardhop makes it fast and easy to add a new. Cardhop1.2.1TNT Cardhop 1.2.1 Mac OS X 10 MB. So far, manage and interact with your contacts has been a real frustration. The analysis engine magical Cardhop is incredibly intuitive Whatever allows you to search, add, edit.
Until now, managing and interacting with your contacts has been a real frustration. Cardhop’s magical parsing engine is incredibly intuitive, letting you search, add, edit, and interact with your contacts using a simple sentence!
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The z-score
The Standard Normal Distribution
Nutxt 3 17 nkjv. Definition of the Standard Normal Distribution The Standard Normaldistribution follows a normal distribution and has mean 0 and standard deviation 1 |
Notice that the distribution is perfectly symmetric about 0.
If a distribution is normal but not standard, we can convert a value to the Standard normal distribution table by first by finding how many standard deviations away the number is from the mean.
The z-score
The number of standard deviations from the mean is called the z-score and can be found by the formula
x - m
z =
s
Example
Find the z-score corresponding to a raw score of 132 from a normal distribution with mean 100 and standard deviation 15. Multipart rar mac.
Solution
We compute
132 - 100
z = = 2.133
15
Example
A z-score of 1.7 was found from an observation coming from a normal distribution with mean 14 and standard deviation 3. Find the raw score.
Solution
We have
x - 14
1.7 =
3
To solve this we just multiply both sides by the denominator 3,
(1.7)(3) = x - 14
5.1 = x - 14
x = 19.1
The z-score and Area
Often we want to find the probability that a z-score will be less than a given value, greater than a given value, or in between two values. To accomplish this, we use the table from the textbook and a few properties about the normal distribution.
Example
Find
P(z < 2.37)
Solution
We use the table. Notice the picture on the table has shaded region corresponding to the area to the left (below) a z-score. This is exactly what we want. Below are a few lines of the table.
z | .00 | .01 | .02 | .03 | .04 | .05 | .06 | .07 | .08 | .09 |
2.2 | .9861 | .9864 | .9868 | .9871 | .9875 | .9878 | .9881 | .9884 | .9887 | .9890 |
2.3 | .9893 | .9896 | .9898 | .9901 | .9904 | .9906 | .9909 | .9911 | .9913 | .9916 |
2.4 | .9918 | .9920 | .9922 | .9925 | .9927 | .9929 | .9931 | .9932 | .9934 | .9936 |
The columns corresponds to the ones and tenths digits of the z-score and the rows correspond to the hundredths digits. For our problem we want the row 2.3 (from 2.37) and the row .07 (from 2.37). The number in the table that matches this is.9911.
Hence
When was pubg released. P(z < 2.37) = .9911
Example
Find https://peddconknafa1974.mystrikingly.com/blog/jackosx.
P(z > 1.82)
Solution
In this case, we want the area to the right of 1.82. This is not what is given in the table. We can use the identity
P(z > 1.82) = 1 - P(z < 1.82)
reading the table gives
P(z < 1.82) = .9656
Our answer is
P(z > 1.82) = 1 - .9656 = .0344
Example
Find
P(-1.18 < z < 2.1)
Solution
Once again, the table does not exactly handle this type of area. However, the area between -1.18 and 2.1 is equal to the area to the left of 2.1 minus the area to the left of -1.18. That is
P(-1.18 < z < 2.1) = P(z < 2.1) - P(z < -1.18)
To find P(z < 2.1) we rewrite it as P(z < 2.10) and use the table to get
P(z < 2.10) = .9821.
The table also tells us that
P(z < -1.18) = .1190
Now subtract to get
P(-1.18 < z < 2.1) = .9821 - .1190 = .8631
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